If a bacterial protein contains 30 amino acids, how many nucleotide bases are needed to code for it?

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Multiple Choice

If a bacterial protein contains 30 amino acids, how many nucleotide bases are needed to code for it?

Explanation:
Proteins are built from amino acids encoded by codons, with each codon made of three nucleotides. So to specify 30 amino acids, you need 30 codons, which is 30 × 3 = 90 nucleotide bases in the coding sequence. The start codon initiates translation and the stop codon terminates it, but the stop codon doesn’t code for an amino acid; it would only add bases if you counted it separately. Here, the bases required to code the amino acid sequence are 90.

Proteins are built from amino acids encoded by codons, with each codon made of three nucleotides. So to specify 30 amino acids, you need 30 codons, which is 30 × 3 = 90 nucleotide bases in the coding sequence. The start codon initiates translation and the stop codon terminates it, but the stop codon doesn’t code for an amino acid; it would only add bases if you counted it separately. Here, the bases required to code the amino acid sequence are 90.

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